To step down a 24V DC source to 12V DC to supply a continuous 10A load (120W output) using modern dc to dc converters with a typical 92% efficiency, your input current will be exactly 5.43A. Because power supplies must be derated for thermal headroom and transient spikes, you need a converter with a minimum continuous rating of 150W. The governing formula is $I_{in} = \frac{V_{out} \times I_{out}}{V_{in} \times \eta}$. Substituting our exact values: $I_{in} = \frac{12V \times 10A}{24V \times 0.92} = 5.434A$.

The Core Conversion Math and Neighboring Load Values

Output power is never perfectly equal to input power. The missing 8% in our calculation is lost to switching losses in the MOSFETs, conduction losses in the inductor, and magnetic core hysteresis. When sizing your input wiring and upstream fuses, you must calculate for the worst-case continuous draw, not just the nominal output.

Below is a spec-sheet-table showing how input current scales across a ±20% load range around our 10A baseline. This is critical for sizing your primary side fuse, which should typically be rated 125% to 150% above the maximum steady-state input current.

Output Current ($I_{out}$)Output Power ($P_{out}$)Input Current ($I_{in}$) @ 92% EffRecommended Input Fuse (Slow-Blow)
8.0A (-20%)96W4.35A6A
9.0A (-10%)108W4.89A7A
10.0A (Baseline)120W5.43A8A
11.0A (+10%)132W5.98A8A
12.0A (+20%)144W6.52A10A

What Assumptions Fix This Answer?

The 5.43A figure is locked in by three hard assumptions: a fixed 92% efficiency, a true 24.0V input, and a purely resistive steady-state load. In the real world, these variables shift.

Bench Reality Check: A '24V' lead-acid battery bank actually sits at 28.8V when fully charged and drops to 21.0V when depleted. If your input voltage sags to 21V under heavy load, your input current jumps to 6.2A ($120W / (21V \times 0.92)$) to maintain the same 120W output. Always size your input wiring for the lowest expected input voltage, not the nominal voltage.

When is this calculation meaningless? Just as power factor renders simple AC wattage calculations useless without phase angle data, steady-state DC-DC math is meaningless if your load transient profile is unknown. If your 10A load is actually a stepper motor or an ESP32 cluster that idles at 2A but spikes to 25A for 50 milliseconds during transmission or microstepping, the average $I_{in}$ calculation won't save you. The converter will hit its internal over-current protection (OCP) and latch off unless it has a peak current rating and sufficient output capacitance to handle the transient. If you don't know the peak-to-average current ratio of your load, steady-state sizing is a guess.

How the Math Shifts Across 12V, 24V, and 48V Architectures

Single-voltage answers are dangerous because input architecture drastically changes conduction losses and topology efficiency. Here is how supplying that exact same 12V / 10A (120W) load shifts when fed from different nominal DC bus voltages:

  • 48V to 12V (Buck): $I_{in} = \frac{120W}{48V \times 0.94} = 2.66A$. High-voltage step-downs are highly efficient (94%+) because input current is low, minimizing $I^2R$ copper losses in the input traces and inductor.
  • 24V to 12V (Buck): $I_{in} = \frac{120W}{24V \times 0.92} = 5.43A$. The standard 2:1 step-down ratio is the sweet spot for most commercial off-the-shelf modules.
  • 12V to 12V (Buck-Boost/SEPIC): $I_{in} = \frac{120W}{12V \times 0.88} = 11.36A$. If you are stabilizing a noisy, sagging 12V alternator rail to a clean 12V logic rail, you need a complex 4-switch buck-boost topology. Efficiency drops to ~88%, and input current nearly doubles the output current.

Decision Tree: Selecting Your Exact Converter Module

Don't just buy a generic '150W step-down module' from an online marketplace; unbranded units often fake their continuous current ratings and lack thermal shutdown. Use this decision-tree-table to lock in your hardware.

Condition / RequirementIf True...If False...
Is the load continuous >8A?Require chassis-mount with integrated heatsink.PCB-mount (SIP/DIP) is acceptable.
Is input voltage subject to spikes >35V?Require wide-input range (18-36V or 9-36V).Standard 24V nominal input is fine.
Do you need galvanic isolation?Select isolated topology (flyback/forward).Non-isolated buck is cheaper and more efficient.

The Concrete Pick: For a 24V-to-12V, 10A continuous industrial application, terminate your search and buy the Mean Well SD-150B-12. It is a 150W non-isolated chassis-mount module with a 19-29VDC input range, built-in constant current limiting, and an integrated aluminum heatsink baseplate. It costs approximately $32 USD, handles the 5.43A input draw effortlessly, and leaves 30W of thermal headroom for 40°C ambient environments.

Frequently Asked Questions

Do I need to worry about power factor with DC to DC converters?
No. Power factor is strictly an AC phenomenon relating to the phase shift between voltage and current waveforms. In DC circuits, voltage and current are in phase (PF = 1.0). The equivalent 'hidden loss' metric in DC-DC conversion is the efficiency curve ($\eta$), which varies based on load percentage and temperature.

Why did my 120W converter shut down when I connected a 10A motor?
DC motors have a locked-rotor inrush current that can be 5x to 7x their running current. Your 10A motor likely pulled 50A+ for a few milliseconds at startup. The converter's OCP tripped. You must either select a converter with a high peak-current tolerance (often marketed as 'motor start capable') or add a soft-start circuit and a large capacitor bank on the output.

Where can I read more about topology selection?
For a deep dive into why buck, boost, and SEPIC topologies behave differently under load, the RECOM Power Knowledge Base provides excellent, math-backed breakdowns of switching regulator design and thermal derating curves.