Reactive power is the portion of AC electricity that oscillates between the source and the load without performing actual work, measured in Volt-Amperes Reactive (VAR). If you are sizing wire for a DC circuit, you only care about watts. But in AC circuits with inductive or capacitive loads, ignoring this oscillating energy will result in undersized breakers, excessive voltage drop, and tripped thermal overloads.
The Core Reactive Power Definition
To understand the reactive power definition deeply, you have to look at how alternating current interacts with magnetic and electric fields. When you power a purely resistive load like an incandescent heater, voltage and current peak at the exact same time. All the energy delivered by the source is converted into heat. That is real power, measured in Watts (W).
However, when you power an induction motor or a transformer, the load contains coils of wire (inductors). Inductors resist changes in current by building a magnetic field. This causes the current waveform to lag behind the voltage waveform. During one part of the AC cycle, the source pushes energy into the magnetic field. During the next part of the cycle, the collapsing magnetic field pushes that exact same energy back to the source.
Because this bouncing energy still has to travel through your wires, it generates heat in the conductors and takes up physical capacity in your transformers and generators. This is what reactive power changes in a real installation: it forces you to use thicker wire and larger breakers to handle the 'sloshing' current, even though that current isn't doing any actual mechanical or thermal work.
The Math: A Worked Numeric Example
Let's put real numbers to this concept using a common bench and jobsite load: a 240V single-phase 3HP induction motor running a table saw.
- Real Power (P): The motor's nameplate indicates it consumes 2200 Watts of real power to cut the wood.
- Power Factor (PF): Under this specific cutting load, the motor operates at a power factor of 0.80 (or 80%).
First, we calculate the Apparent Power (S), which is the total power the utility must supply. Apparent power is measured in Volt-Amperes (VA).
S = P / PF
S = 2200W / 0.80 = 2750 VA
Next, we find the actual current flowing through the wires. This is the number that dictates your wire gauge and breaker size.
I = S / V
I = 2750 VA / 240V = 11.45 Amps
Finally, we calculate the Reactive Power (Q) using the power triangle formula: Q = √(S² - P²).
Q = √(2750² - 2200²)
Q = √(7,562,500 - 4,840,000)
Q = √2,722,500 = 1650 VAR
Even though the motor only does 2200W of real work, your wiring must handle 11.45A of total current. If you had mistakenly sized your wire for just the real power (2200W / 240V = 9.16A), you would have undersized the circuit by over 20%.
Where You Meet Reactive Power in Practice
You won't see reactive power on a standard residential electric bill, but it dictates how commercial and industrial electrical systems are designed. Here is where it shows up on the jobsite:
- Induction Motors: HVAC compressors, air handlers, and machine shop lathes are highly inductive. A motor running under light load can have a power factor as low as 0.50, meaning half the current is just reactive slosh.
- Transformers and Welders: Stick welders and microwave oven transformers rely on magnetic fields to step voltages up or down. They draw massive reactive current, which is why a 120V microwave might pull 15A of apparent current while only heating food with 1000W of real power.
- Cheap LED Drivers: Low-quality commercial LED fixtures often lack internal power factor correction (PFC) capacitors. A 100W LED high-bay light might pull 160VA from the panel, forcing facility managers to upsize branch circuit wiring.
- Utility Penalties: Commercial facilities are often billed for kVARh (kilovolt-ampere-reactive hours). If a factory's power factor drops below 0.90, the utility charges a penalty because the reactive current is heating up the utility's distribution transformers without generating billable watt-hours. For a deeper look at how utilities measure this, refer to Fluke's guide on power factor and power quality.
Real-World Scenario: The 5HP Compressor Voltage Drop
To see how ignoring the reactive power definition causes real failures, let's walk through a common workshop mistake.
Setup: A hobbyist is adding a 5HP (approx. 3730W mechanical output) 240V single-phase air compressor to their garage. The electrical panel is 120 feet away. The compressor nameplate lists a Full Load Amps (FLA) of 18A, but the hobbyist decides to calculate the wire size based on the real power output to save money. They estimate 4500W of electrical real power input. They divide 4500W by 240V, get 18.75A, and decide to run 12 AWG NM-B cable on a 20A breaker, assuming it perfectly matches the real power draw.
Numbers: The 12 AWG copper wire has a resistance of roughly 1.93 ohms per 1000 feet. The total round-trip wire length is 240 feet. The actual motor power factor under continuous pumping load is 0.75. Therefore, the Apparent Power is 4500W / 0.75 = 6000 VA. The actual current flowing through the wire is 6000 VA / 240V = 25 Amps.
Outcome: The moment the compressor reaches its cut-in pressure and the motor runs continuously, the 20A breaker trips. When the hobbyist resets it and forces the motor to run, the 12 AWG wire becomes noticeably warm to the touch, and the compressor struggles to build pressure due to severe voltage sag at the motor terminals.
What went wrong: The hobbyist sized the circuit for real power (18.75A) instead of apparent power (25A). The 1650+ VAR of reactive power demanded an extra 6+ Amps of current that the 12 AWG wire and 20A breaker were never rated to handle. Furthermore, the voltage drop was calculated on 25A, not 18.75A, resulting in a drop of nearly 12V (5%). The motor starved for voltage, drew even more current to compensate, and tripped the thermal overload. For proper motor circuit sizing, one must always follow AC power triangle principles and NEC Article 430, which requires sizing conductors at 125% of the motor FLA.
What People Commonly Confuse It With
When diagnosing power quality issues with a meter like a Fluke 435 Power Quality Analyzer, it is easy to mix up reactive power with other AC anomalies.
- Harmonics (THD): Harmonics are high-frequency distortions caused by non-linear loads like VFDs (Variable Frequency Drives) and switching power supplies. While harmonics also cause excess current and heat, they are a distortion of the waveform shape, not a phase-shift oscillation. Reactive power is strictly a fundamental frequency (50/60Hz) phase-shift issue.
- Apparent Power: Apparent power (VA) is the vector sum of real power and reactive power. People often confuse the two, thinking reactive power is the total power. Remember: Apparent power is what the utility supplies; reactive power is just the 'useless' portion of that apparent power.
- Inrush Current: A motor might draw 600% of its FLA for the first 200 milliseconds when starting. This is inrush current, caused by the physical inertia of the rotor and the initial magnetization of the core. Reactive power, however, is a steady-state condition that persists as long as the motor is running and maintaining its magnetic field.
FAQ: Reactive Power and Power Factor Correction
Can I just add a capacitor to fix reactive power at home?
Yes, technically. Capacitors act as a local source of reactive power. By wiring a run capacitor in parallel with an inductive motor, the magnetic field sloshes energy back and forth between the motor's inductor and the capacitor, rather than traveling all the way back to the utility transformer. This is called Power Factor Correction (PFC). However, in a residential setting, utilities do not charge you for kVARh, so the cost of buying and safely wiring properly rated AC capacitors will never yield a return on investment.
Does reactive power consume fuel at the power plant?
Not directly, but it causes real power losses. The reactive current still flows through the resistance of the transmission lines, generating I²R heat losses. The power plant's generators must be physically larger to handle the total apparent current, and the utility must burn slightly more coal or gas to make up for the heat lost in the transmission lines due to the reactive current.
Why do cheap multimeters give me the wrong current reading on a motor?






