For a standard 4,800W resistive load (like a typical residential electric water heater), 240V is exactly 20 amps. Because volts and amps measure different electrical properties, you cannot convert them without a third variable: watts. Using the foundational single-phase AC formula Amps = Watts ÷ Volts, we substitute our baseline values to get 20A = 4800W ÷ 240V. If your specific appliance wattage differs, your amperage shifts proportionally. Below is the exact math, the edge cases that break the formula, and the decision path to size your breaker correctly.

The Core Formula and Baseline Assumptions

To calculate amperage from voltage and wattage, we rely on Watt's Law. For standard North American residential 240V circuits (which are actually split-phase, utilizing two 120V legs 180° out of phase), the formula is:

I = P ÷ V

  • I = Current in Amps
  • P = Real Power in Watts
  • V = Voltage (240V)

The critical assumption: This direct division only yields the correct amperage if the load is purely resistive (Power Factor = 1.0). Resistive loads include baseboard heaters, electric ovens, water heaters, and incandescent lighting. In these circuits, voltage and current waveforms are perfectly in phase, meaning all the power drawn from the panel is converted into useful work (heat or light).

Neighboring Values: 240V Amp Draw Chart (±20% Range)

If your load is close to our 4,800W baseline, use this reference table to find your exact amperage. This covers a ±20% variance, capturing most standard residential 240V appliances from compact dryers to large water heaters.

Appliance Wattage (W) Voltage (V) Calculated Amps (A) Typical Appliance Match
3,840W (-20%) 240V 16.0A Small portable spa / 2-ton AC compressor
4,320W (-10%) 240V 18.0A Standard electric clothes dryer (heating element)
4,800W (Baseline) 240V 20.0A 40-gallon electric water heater
5,280W (+10%) 240V 22.0A 50-gallon electric water heater / Wall oven
5,760W (+20%) 240V 24.0A Heavy-duty baseboard heater array

How the Math Shifts Across 120V, 230V, and 3-Phase

Voltage is not a universal constant. If you move this same 4,800W load to a different system architecture, the amperage shifts dramatically.

120V Systems (Standard Branch Circuits)

If you attempt to pull 4,800W from a standard 120V outlet, the amperage doubles. 4800W ÷ 120V = 40A. This exceeds the capacity of any standard 15A or 20A receptacle and will instantly trip the breaker. This is precisely why high-wattage appliances mandate 240V circuits: doubling the voltage halves the current, allowing for smaller, cheaper wire.

230V Systems (Motor Nameplates and EU Mains)

Many industrial motors and European appliances are rated at 230V, not 240V. If your equipment nameplate specifies 230V, your amperage increases slightly. 4800W ÷ 230V = 20.86A. While a fraction of an amp seems negligible on a bench, it matters when sizing conductors near their thermal limits.

3-Phase Systems (Commercial/Industrial)

In a 240V 3-phase delta system, the power is distributed across three legs. The formula introduces the square root of 3 (1.732): I = P ÷ (V × 1.732). For our 4,800W load: 4800 ÷ (240 × 1.732) = 11.54A. Three-phase systems deliver the same power with significantly less current per conductor.

When the Conversion is Meaningless: The Power Factor Trap

The I = P ÷ V conversion becomes dangerously inaccurate when applied to inductive loads—specifically AC motors, HVAC compressors, and large transformers—without accounting for Power Factor (PF).

Bench Reality: Inductive loads cause the current waveform to lag behind the voltage waveform. The utility must supply more "apparent power" (VA) to achieve the same "real power" (W).

If you are sizing a circuit for a 4,800W (approx. 6.4 HP) 240V air compressor motor, and you assume PF = 1.0, you will calculate 20A. However, typical single-phase induction motors operate at a PF of roughly 0.80 to 0.85. Furthermore, motors have efficiency losses. According to Fluke's power quality guidelines, you must measure or calculate apparent power to find true current draw.

The corrected formula: I = P ÷ (V × PF × Efficiency)

If PF is 0.85 and motor efficiency is 0.90: 4800 ÷ (240 × 0.85 × 0.90) = 26.1A. If you sized your breaker for 20A based on the basic formula, the motor will trip the breaker on startup or overheat the conductors during continuous run. When PF is unknown, the basic conversion is meaningless; always use the Full Load Amps (FLA) stamped directly on the motor nameplate instead of calculating from wattage.

Decision Path: Sizing Your 240V Breaker and Wire

Calculating the amp draw is only step one. Step two is sizing the overcurrent protective device (breaker) and the conductor (wire) to comply with NFPA 70 (NEC) standards. Use this decision tree to terminate on the exact parts you need to buy.

Load Type & Calculated Amps NEC Rule Applied Required Breaker Size Required Copper Wire (NM-B / THHN)
Resistive, < 16A continuous Standard sizing (NEC 240.4) 20A Double-Pole 12 AWG
Resistive, 16A - 24A continuous 125% Continuous Load Rule (NEC 210.20) 30A Double-Pole 10 AWG
Resistive, 24A - 32A continuous 125% Continuous Load Rule 40A Double-Pole 8 AWG
Resistive, 32A - 40A continuous 125% Continuous Load Rule 50A Double-Pole 6 AWG

The Concrete Pick for a 20A Water Heater

Let's terminate the decision path for our baseline 4,800W (20A) electric water heater. A water heater is classified as a continuous load because it can run at maximum current for three hours or more.

NEC Article 210.20(A) requires the branch circuit rating to be at least 125% of the continuous load.

  • 20A × 1.25 = 25A minimum breaker rating.
  • The next standard breaker size up from 25A is 30A (per NEC 240.6).

Your Exact Parts List:

  1. Breaker: 30-Amp, 2-Pole (e.g., Square D HOM230 for Homeline panels or Eaton BR230 for BR panels).
  2. Wire: 10 AWG NM-B (Romex) if running through standard residential framing, or 10 AWG THHN in conduit. Ensure terminations are torqued to the manufacturer's spec (typically 20-25 in-lbs for 10 AWG) to prevent thermal creep.

Frequently Asked Questions

Can I use a 20A breaker for a 20A 240V load?
Only if the load is strictly non-continuous (runs for less than 3 hours at a time), like a table saw or a welder. For continuous loads like heaters, you must apply the 125% multiplier and step up to a 25A or 30A breaker.

Does 240V require a neutral wire?
Pure 240V resistive loads (like baseboard heaters) only require two hot wires and a ground. However, appliances with 120V control boards or timers (like electric dryers and ranges) require a neutral wire to complete the 120V circuit, necessitating a 4-wire setup (Hot, Hot, Neutral, Ground).