If you are sizing a long DC solar run or checking voltage drop on an AC branch circuit, the resistance of your wire changes as it heats up under load. An RT calculator (Resistance at Temperature) solves this using the linear temperature coefficient formula. The direct answer for standard building wire is the linear approximation formula: Rt = Rref × [1 + α × (Tt - Tref)]. For copper at a 20°C reference, α is 0.00393, and for aluminum, it is 0.00403.

Ignoring this temperature shift is a classic jobsite mistake. A wire that meets a 3% voltage drop limit on a cool morning might exceed it by mid-afternoon when the attic hits 130°F and the wire is carrying continuous current. Here is the exact math, the assumptions, and the worked examples you need to use an RT calculator effectively.

The Core RT Formula and Symbol Definitions

The fundamental equation used by any standard RT calculator for copper and aluminum conductors is:

Rt = Rref × [1 + αref × (Tt - Tref)]

Symbol Definition Standard Units Typical Values / Notes
Rt Resistance at the target operating temperature Ohms (Ω) The final value you are solving for in voltage drop calculations.
Rref Resistance at the known reference temperature Ohms (Ω) Sourced from NEC Chapter 9, Table 8 (usually at 20°C / 68°F).
αref Temperature coefficient of resistance Per °C (1/°C) Cu: 0.00393; Al: 0.00403 (at 20°C reference).
Tt Target operating temperature of the conductor Degrees Celsius (°C) Ambient temp + temperature rise from I²R heating.
Tref Reference temperature for Rref and α Degrees Celsius (°C) Almost always 20°C in standard US/EU wire tables.

When the Formula Applies and Its Assumptions

This linear formula assumes the temperature coefficient (α) remains constant. According to Georgia State University's HyperPhysics, this linear approximation is highly accurate for copper and aluminum between 0°C and 100°C. If you are calculating resistance for RTD sensors (like a PT100) at 400°C, or dealing with extreme cryogenic temperatures, this linear formula breaks down and you must use the Callendar-Van Dusen equation or Steinhart-Hart equation for thermistors. For standard THHN, XHHW, and NM-B building wires operating within their 60°C, 75°C, or 90°C insulation ratings, the linear RT calculator formula is perfectly valid.

Rearranged Forms for Bench and Field Use

On the bench, you rarely just solve for Rt. Often, you measure a hot wire's resistance with a milliohm meter and need to back-calculate its temperature, or you need to find the baseline resistance. Here are the algebraically rearranged forms:

  • Solve for Target Temperature (Tt):
    Tt = [ (Rt / Rref) - 1 ] / αref + Tref
    Use case: You measure the resistance of a motor winding or feeder and want to know how hot it is actually running.
  • Solve for Reference Resistance (Rref):
    Rref = Rt / [ 1 + αref × (Tt - Tref) ]
    Use case: You measured a wire's resistance in a hot attic and need to know what the NEC table value should be to verify the wire gauge.
  • Solve for Temperature Coefficient (αref):
    αref = [ (Rt / Rref) - 1 ] / (Tt - Tref)
    Use case: Identifying an unknown alloy wire sample in the lab.

Solved Problems with Strict Unit Tracking

Let's run two practical calculations. We will use the standard copper α20 of 0.00393 and aluminum α20 of 0.00403, referencing the All About Circuits DC textbook chapter on temperature coefficients.

Problem 1: Copper Branch Circuit in a Hot Attic

Setup: You have a 250-foot run (one way) of 10 AWG solid copper wire. NEC Chapter 9, Table 8 lists the DC resistance of 10 AWG copper as 1.24 Ω per 1,000 feet at 20°C. The wire is in an attic that reaches 50°C ambient, and under continuous load, the wire's internal I²R heating pushes its actual operating temperature (Tt) to 65°C. What is the total loop resistance at operating temperature?

  1. Calculate Rref (Total baseline resistance):
    (250 ft × 2 for loop) = 500 ft total.
    R20 = (500 ft / 1000 ft) × 1.24 Ω = 0.620 Ω.
  2. Identify knowns:
    Rref = 0.620 Ω
    α20 = 0.00393 /°C
    Tref = 20°C
    Tt = 65°C
  3. Apply the RT formula:
    R65 = 0.620 × [1 + 0.00393 × (65 - 20)]
    R65 = 0.620 × [1 + 0.00393 × 45]
    R65 = 0.620 × [1 + 0.17685]
    R65 = 0.620 × 1.17685
  4. Final Result:
    R65 = 0.7296 Ω.
    Note: The resistance increased by nearly 18% purely due to heat. If you calculated voltage drop using the 20°C table value, your actual drop will be 18% higher than predicted.

Problem 2: Back-Calculating Aluminum Feeder Temperature

Setup: You have a 1/0 AWG aluminum feeder. The NEC table value (R20) is 0.194 Ω/1000ft. For a 200-foot one-way run (400 ft loop), Rref = 0.0776 Ω. Under full load, you measure the loop resistance with a calibrated micro-ohmmeter and read 0.0910 Ω. How hot is the wire?

  1. Identify knowns:
    Rt = 0.0910 Ω
    Rref = 0.0776 Ω
    α20 (Aluminum) = 0.00403 /°C
    Tref = 20°C
  2. Apply the rearranged formula for Tt:
    Tt = [ (0.0910 / 0.0776) - 1 ] / 0.00403 + 20
    Tt = [ 1.17268 - 1 ] / 0.00403 + 20
    Tt = 0.17268 / 0.00403 + 20
  3. Final Result:
    Tt = 42.85 + 20 = 62.85°C.
    The wire is running at roughly 63°C. If this is a 75°C rated termination, you are safely within limits, but approaching the threshold where derating factors might apply if bundled with other conductors.

Real-World Scenario: The Undersized Solar Feeder

Abstract math is fine for exams, but on the jobsite, ignoring the RT calculator leads to callbacks. Here is a scenario from a 48V off-grid solar install that went wrong.

  • The Setup: A 48V battery bank feeding a 3000W inverter via 4 AWG copper wire. The one-way distance was 15 feet. The installer used a standard voltage drop calculator at 20°C, which showed a 0.8% drop at 62.5A (3000W / 48V). Well under the 1% recommended limit for DC battery cables.
  • The Numbers: 4 AWG copper is 0.308 Ω/1000ft. For a 30ft loop, R20 = 0.00924 Ω. At 62.5A, the calculated drop was 0.57V. However, the cables were routed through a mechanical closet that hit 45°C ambient, and the continuous 62.5A load added internal heating. Using the RT formula for an estimated Tt of 80°C: R80 = 0.00924 × [1 + 0.00393 × (80 - 20)] = 0.01142 Ω. The actual voltage drop became 0.71V.
  • The Outcome: The inverter's low-voltage disconnect (LVD) was set to 46V. Under heavy surge loads (like a microwave starting), the voltage at the inverter terminals sagged below 46V, tripping the inverter offline repeatedly during dinner prep.
  • What Went Wrong: The installer sized the wire based on 20°C ampacity and resistance tables without accounting for the ambient temperature of the closet or the I²R heating of the wire itself. The 22% increase in resistance pushed the voltage sag past the inverter's threshold. The fix was upgrading to 2/0 AWG copper to lower the baseline Rref and reduce the thermal mass heating.

Unit Mistakes That Break the Math and Realistic Magnitudes

When punching numbers into an RT calculator, two specific mistakes will instantly ruin your design.

The Fahrenheit Trap

The temperature coefficient (α) for copper (0.00393) and aluminum (0.00403) is strictly defined per degree Celsius. If your field thermometer reads 140°F and you plug 140 into the Tt variable, your calculated resistance will be astronomically high, and you will massively oversize your wire. You must convert Fahrenheit to Celsius first: °C = (°F - 32) × 5/9. 140°F is 60°C. Always track your units through the parenthesis.

Mismatched Reference Temperatures

Some European datasheets and specific motor winding specs use an α value referenced to 0°C (α0 for copper is roughly 0.00427) or 25°C. If you use an α20 value (0.00393) but pair it with an Rref pulled from a table that was measured at 25°C, your baseline is corrupted. Always verify that your Rref table and your α value share the exact same Tref subscript. NEC Chapter 9 Table 8 is explicitly based on 20°C (68°F).

What a Realistic Answer Magnitude Looks Like

Develop a gut feeling for the numbers. For standard building wire (14 AWG through 4/0 AWG), resistance is measured in milliohms per foot. If your RT calculator spits out 15.4 Ω for a 100-foot run of 12 AWG copper, you missed a decimal point or failed to divide the 'Ohms per 1000ft' table value by 1000. A 100-foot one-way run (200ft loop) of 12 AWG copper should have a baseline resistance of roughly 0.396 Ω at 20°C, rising to about 0.465 Ω at 75°C. If your final Rt isn't in the sub-ohm range for typical branch circuit lengths, re-check your Rref input.