The Formula for Synchronous Speed: Direct Answer & Symbol Table
The formula for synchronous speed—the theoretical rotational velocity of the stator's magnetic field in an AC motor—is:
Ns = (120 × f) / P
Where the constant 120 is derived from multiplying 60 seconds per minute by 2 (representing the North and South pole halves of a single electrical cycle). This formula dictates the absolute speed limit of the rotating magnetic field before accounting for mechanical slip.
| Symbol | Parameter | Standard Unit | Definition & Constraints |
|---|---|---|---|
| Ns | Synchronous Speed | RPM (Revolutions Per Minute) | Speed of the stator's rotating magnetic field. Must be a discrete step value based on grid frequency. |
| f | AC Line Frequency | Hz (Hertz) | Supply frequency. Nominally 60 Hz (North America) or 50 Hz (Europe/Asia). VFD output frequency can range from 0-400+ Hz. |
| P | Total Magnetic Poles | Integer (Unitless) | The total count of individual magnetic poles (N and S) established by the stator winding. Must be an even integer (2, 4, 6, 8...). |
What a Realistic Answer Magnitude Looks Like
Because P must be an even integer, synchronous speeds are not continuous; they fall into fixed "steps" dictated by your local grid. If your calculated answer falls between these steps, you have made a math error or misread the motor nameplate.
- 60 Hz Grid (North America): 3600 RPM (2-pole), 1800 RPM (4-pole), 1200 RPM (6-pole), 900 RPM (8-pole), 720 RPM (10-pole).
- 50 Hz Grid (IEC Regions): 3000 RPM (2-pole), 1500 RPM (4-pole), 1000 RPM (6-pole), 750 RPM (8-pole), 600 RPM (10-pole).
Note: Actual rotor speed on an induction motor nameplate will always be 2% to 5% lower than these values due to slip (e.g., a 4-pole 60Hz motor will have a synchronous speed of 1800 RPM, but a nameplate rated speed of 1750 RPM).
Rearranged Forms & Unit Mistakes That Break the Math
On the bench or in the field, you rarely just solve for Ns. You often need to identify an unmarked motor's pole count or verify a VFD's output frequency. Here are the algebraic rearrangements:
Rearranged Forms List
- To find Frequency (f):
f = (Ns × P) / 120 - To find Poles (P):
P = (120 × f) / Ns
Critical Unit Traps
The formula for synchronous speed is unforgiving if you mix up your terminology. Watch out for these three common mistakes:
- Pole Pairs vs. Total Poles: European IEC datasheets frequently specify pole pairs (denoted as p) rather than total poles (P). Since one pair equals two poles, P = 2p. If a Siemens datasheet lists "2 pole pairs", you must use P = 4 in the formula, not 2.
- Radians per Second (rad/s): In physics and advanced control theory (like Field Oriented Control for BLDCs), speed is measured in electrical radians per second (ωs). The RPM formula fails here. The correct rad/s formula is
ωs = (4π × f) / P. - Confusing Synchronous Speed with Rotor Speed: Ns is the speed of the magnetic field, not the physical shaft. If you plug a nameplate's 1725 RPM into the Ns variable to find the poles, the math will yield 4.17 poles. Poles must be whole even numbers; this discrepancy is the slip required to induce rotor current.
Worked Examples with Strict Unit Tracking
Let's run through two real-world scenarios, tracking units at every step to ensure the dimensional analysis holds up.
Problem 1: Finding Synchronous Speed for a VFD-Driven Motor
Scenario: You are programming a Yaskawa GA800 VFD to run a 6-pole AC induction motor at exactly 45 Hz to match a conveyor belt's required line speed. What is the new synchronous speed of the magnetic field?
- Identify knowns: f = 45 Hz, P = 6 poles.
- Select formula: Ns = (120 × f) / P
- Substitute values: Ns = (120 × 45) / 6
- Calculate numerator: 120 × 45 = 5400
- Divide by poles: 5400 / 6 = 900
- Final Answer: Ns = 900 RPM. (The physical shaft will turn slightly slower, roughly 860-880 RPM, depending on the motor's slip at that specific load).
Problem 2: Identifying an Unmarked Motor's Pole Count
Scenario: You have a salvaged 3-phase motor with a faded nameplate. You know it was pulled from a 50 Hz European facility, and your tachometer reads the physical shaft spinning at 965 RPM under no load. How many poles does the stator have?
- Identify knowns: f = 50 Hz. Rotor speed = 965 RPM.
- Estimate Ns: Because no-load slip is very small (typically < 1%), the synchronous speed Ns must be the next standard 50 Hz step above 965 RPM. Looking at our magnitude list, the closest step is 1000 RPM.
- Select rearranged formula: P = (120 × f) / Ns
- Substitute values: P = (120 × 50) / 1000
- Calculate numerator: 120 × 50 = 6000
- Divide by Ns: 6000 / 1000 = 6
- Final Answer: The motor has 6 poles (or 3 pole pairs). The slip is (1000 - 965) / 1000 = 3.5%, which is perfectly normal for a standard efficiency induction motor under minimal load.
When the Formula Applies (and Its Core Assumptions)
The formula for synchronous speed is a fundamental law of AC electromagnetism, but it is strictly bound to specific machine topologies. According to the All About Circuits AC Motors textbook, the formula relies on the creation of a balanced, rotating magnetic field.
Where it Applies
- 3-Phase AC Induction Motors (Squirrel Cage & Wound Rotor): Dictates the stator field speed. Rotor speed requires subtracting slip.
- AC Synchronous Motors (Reluctance, Permanent Magnet, Excited): Dictates both the stator field speed and the exact physical rotor speed (slip is zero).
- Single-Phase AC Motors (with start/run windings): Applies to the main running winding's equivalent rotating field.
Where it Fails (Do Not Use)
- Brushed DC Motors: Speed is governed by back-EMF and armature voltage (N ∝ V / Φ), not AC frequency.
- Stepper Motors: Speed is determined by the controller's pulse rate (Hz) and the mechanical step angle (e.g., 1.8°), not stator pole counts in the traditional AC sense.
- Universal Motors: Found in power tools and vacuums; these run on AC or DC and their speed is limited only by mechanical friction and load, often exceeding 20,000 RPM.
Decision Path: Selecting the Right Motor for Your Target RPM
Knowing the formula for synchronous speed is only half the battle. The real engineering challenge is selecting the right hardware to achieve your target mechanical output. Use this decision tree to terminate your design process with a concrete hardware pick.
| Application Requirement | If-Then Logic | Concrete Hardware Pick |
|---|---|---|
| Exact Grid-Locked Speed (e.g., synchronous clocks, grid-tied alternators, precision timing conveyors) |
IF slip is unacceptable and speed must perfectly match Ns regardless of load fluctuations... | Permanent Magnet Synchronous Motor (PMSM). Pick: WEG W22 Magnet line. Zero slip, high efficiency. |
| Variable Speed / Wide RPM Range (e.g., workshop lathes, HVAC fans, pump curves) |
IF you need to dynamically alter 'f' in the formula to change Ns on the fly... | Standard 4-Pole Induction Motor + VFD. Pick: Baldor-Reliance EM3615T (1800 RPM sync) paired with a Yaskawa GA800 VFD. |
| High Torque at Low RPM (e.g., ball mills, rock crushers, direct-drive mixers) |
IF increasing 'P' to lower Ns results in a physically massive motor, and gearboxes introduce unacceptable backlash... | High-Pole-Count Direct Drive or Gear-Reduced. Pick: SEW-EURODRIVE DR.. series 12-pole motor, or a standard 4-pole with a Dodge Torque-Arm II shaft-mount reducer. |
The Default Recommendation
If you are designing a general-purpose automated system, building a DIY workshop machine, or replacing a failed component without strict synchronous timing requirements, default to a 4-pole (1800 RPM synchronous / 1750 RPM rated) NEMA Premium TEFC induction motor controlled by a VFD.
According to the U.S. Department of Energy's Motor Selection Guide, 4-pole motors represent the vast majority of industrial stock. They offer the best balance of physical size, starting torque, and cost. By pairing it with a VFD, you effectively decouple the motor from the rigid constraints of the 120f/P formula, allowing you to dial in any frequency (and thus any synchronous speed) your application demands, right from the HMI screen.






