To run a continuous 1000W AC load through a 12V DC to AC converter circuit (assuming a standard 85% inverter efficiency), you must supply 98.0 Amps of DC current from your battery bank.

The foundational formula used here is:
DC Amps = AC Watts / (DC Volts × Inverter Efficiency)
Substituting our values: 1000W / (12V × 0.85) = 98.04A.

Because battery voltage sags under heavy load and inverter efficiency fluctuates, here is the conversion table for a ±20% range around that 1000W baseline:

AC Load (Watts)DC Current at 12V (Amps)
800W78.4 A
900W88.2 A
1000W98.0 A
1100W107.8 A
1200W117.6 A

The Core Conversion: AC Watts to DC Amps Across System Voltages

The assumption that fixes the answer above is a Power Factor (PF) of 1.0 (purely resistive loads like heaters or incandescent bulbs), an inverter efficiency of 85%, and a nominal 12V DC bus. In reality, a "12V" battery rests around 12.6V but sags to 11.5V under a 100A load. Sizing your wire and fuses based on the nominal 12V (or even the sagged 11.5V) ensures you account for this worst-case voltage drop, which pushes the amperage higher to maintain the same wattage output.

Below is a data-dense reference chart for common appliances. This table assumes an 85% conversion efficiency and a Power Factor of 1.0, mapping the required DC input current across 12V, 24V, and 48V architectures.

AC Appliance / LoadAC WattsDC Amps (12V System)DC Amps (24V System)DC Amps (48V System)Recommended Min Inverter Size
Microwave (Compact)700W68.6 A34.3 A17.2 A1000W
Coffee Maker1200W117.6 A58.8 A29.4 A1500W
Space Heater (Low)1500W147.1 A73.5 A36.8 A2000W
RV Air Conditioner1800W176.5 A88.2 A44.1 A3000W
Well Pump (1/2 HP)1000W (Run)98.0 A49.0 A24.5 A2000W (for surge)

Notice how stepping up to a 48V DC to AC converter circuit cuts the DC current draw by 75% compared to a 12V system. This is why 48V is the standard for residential solar and large off-grid battery banks; it keeps DC currents low enough to use smaller, cheaper wire (e.g., 6 AWG instead of 4/0 AWG) and minimizes I²R heat losses across the busbars.

How 120V, 230V, and 3-Phase Shift the DC Draw

A common misconception is that changing the AC output voltage of the inverter changes the DC input current. It does not. The DC to AC converter circuit draws DC watts based on the AC watts demanded by the load, regardless of whether the output is 120V (North America) or 230V (Europe/Asia). A 1500W space heater will pull 147.1A from a 12V battery whether it is plugged into a 120V or 230V inverter.

However, the system architecture shifts in practice:

  • 120V vs 230V Single-Phase: While the DC draw remains identical for the same wattage, 230V inverters often utilize higher-frequency switching and different transformer topologies that can push peak efficiency closer to 90-92%, slightly reducing the DC amp draw compared to older 120V modified-sine units.
  • 3-Phase Inverters: Used for heavy industrial motors or large commercial HVAC, 3-phase DC to AC converters distribute the load across three AC legs. The total DC wattage drawn is still Total AC Watts / Efficiency, but the internal MOSFET/IGBT switching losses are distributed differently. Furthermore, 3-phase systems rarely run on 12V or 24V DC; they almost exclusively operate on high-voltage DC buses (e.g., 300V-800V DC from a string of batteries or a rectified grid tie), making the low-voltage DC amp calculations irrelevant.

When the Conversion is Meaningless: Power Factor and Surge

The math above completely breaks down when the Power Factor (PF) is unknown or when dealing with inductive loads. If you are running an AC motor, a refrigerator compressor, or a shop vacuum, the nameplate "Watts" often only tells half the story.

Inductive loads require Apparent Power (VA), not just Real Power (Watts). If a motor has a PF of 0.7, it draws 30% more current from the inverter than a resistive heater of the same wattage. The formula shifts to:

DC Amps = (AC Watts / Power Factor) / (DC Volts × Efficiency)

More critically, the surge current (Locked Rotor Amps, or LRA) required to start a compressor can be 5 to 7 times the running wattage for a few seconds. If your 1000W well pump has a 5000W startup surge, your 12V DC to AC converter circuit must momentarily supply 490 Amps. If your battery BMS, busbars, or wiring cannot handle a 490A transient, the inverter will trigger a low-voltage cutoff and trip offline, regardless of your continuous wire sizing.

Surge Sizing Rule: Always size your DC-side fuses and wiring for the inverter's maximum continuous output rating, not just your expected load. A 3000W inverter on a 12V system requires wiring and a fuse rated for at least 350A continuous (3000W / 11.5V sag / 0.85 efficiency = 306A), even if you only plan to run a 500W TV.

Sizing Wire and Fuses for the DC Side

Once you have your worst-case DC ampacity, you must select the correct wire gauge and overcurrent protection. According to standard NEC-style ampacity tables (using the 75°C column for typical inverter terminals), here is the baseline for copper THHN or fine-stranded battery cable:

Max DC CurrentMinimum Copper AWGRecommended ANL / Class T Fuse
Up to 50A8 AWG60A
Up to 100A4 AWG125A
Up to 150A2 AWG175A
Up to 200A1/0 AWG225A
Up to 300A3/0 AWG350A
Up to 400A+4/0 AWG (or parallel runs)500A Class T

When terminating a DC to AC converter circuit, never use solid THHN wire directly into the inverter's high-strand-count lugs if you can avoid it; the vibration and thermal cycling will loosen solid wire over time. Use fine-stranded welding cable or battery cable (like SAE J1127) with a closed-end copper lug, crimped with a hex-die tool and sealed with adhesive-lined heat shrink. For high-current systems (over 200A), always use Class T fuses rather than ANL fuses, as Class T fuses have a higher interrupt capacity (AIC) capable of safely stopping a lithium battery short circuit.

For a deeper look at inverter efficiency curves and thermal derating, consult manufacturer documentation from brands like Victron Energy or Samlex America. Additionally, understanding how power factor impacts your multimeter readings is critical when troubleshooting; Fluke's guide on power factor provides excellent bench-level diagnostics for inductive loads.

Frequently Asked Questions

Does inverter waveform (Pure Sine vs. Modified Sine) change the DC amp draw?
Yes. Modified sine wave inverters are generally less efficient (often 75-80%) and cause inductive loads to run hotter, drawing more VA. Pure sine wave DC to AC converter circuits operate closer to 88-93% efficiency, reducing your DC battery draw for the same AC output.

Why does my multimeter show higher DC amps than the formula predicts?
If your measured DC amps exceed the calculated value, your battery voltage is likely sagging below 12V under load, or your AC load has a poor power factor. Measure the DC voltage at the inverter terminals (not the battery posts) while the load is running to get the true voltage for your formula.