When off-grid builders, van-lifers, and DIYers search for a d to a converter (common shorthand for a DC-to-AC power inverter), they are almost always trying to size the inverter for a specific AC load. For a baseline 1500W continuous AC load at 120V single-phase with a 0.8 power factor (PF), you need an inverter rated for at least 15.6 Amps AC (1875 VA). Factoring in a standard 20% surge headroom for motor startups and inverter efficiency losses, the direct answer is to install a 2000W continuous pure sine wave DC to AC converter.

The governing formula for AC current is I = P / (V × PF). Substituting our baseline values: I = 1500W / (120V × 0.8) = 15.625A. Below, we break down how this math shifts across different global voltages and how to pick the exact hardware for your bench or rig.

The Core Assumptions: Voltage, Phase, and Power Factor

Any DC-to-AC conversion is only as accurate as the assumptions locking it in place. If you change one of the following three variables, your required inverter size changes dramatically:

  • Voltage (V): Nominal AC output. In North America, this is typically 120V or 240V split-phase. In Europe and much of the world, it is 230V.
  • Phase: Single-phase (standard residential) vs. 3-phase (industrial/large marine). 3-phase systems divide the load across three conductors, drastically reducing the current per leg.
  • Power Factor (PF): The ratio of real power (Watts) to apparent power (VA). Resistive loads (heaters, incandescent bulbs) have a PF of 1.0. Inductive loads (compressors, power tools, microwaves) typically sit between 0.6 and 0.8.
When the Conversion is Meaningless: If you are sizing a d to a converter for a mixed load panel and the Power Factor is completely unknown, calculating exact amperage is a guessing game. In these scenarios, you must default to a PF of 0.6 (the worst-case scenario for heavy inductive machinery) or use a True-RMS clamp meter on the AC output of a test inverter to measure apparent power (VA) directly. Never size an inverter assuming a 1.0 PF for a workshop environment.

Load Conversion Table: 1500W Baseline (±20% Range)

The following spec-sheet-table maps the AC current draw and minimum required inverter capacity for loads clustering around our 1500W baseline, assuming a standard 120V single-phase output and a conservative 0.8 PF.

AC Load (Watts) Power Factor AC Voltage Calculated AC Amps Apparent Power (VA) Min. Inverter Size
1200W 0.8 120V 12.5A 1500 VA 1500W / 15A
1350W 0.8 120V 14.1A 1688 VA 2000W / 20A
1500W 0.8 120V 15.6A 1875 VA 2000W / 20A
1650W 0.8 120V 17.2A 2063 VA 2500W / 25A
1800W 0.8 120V 18.8A 2250 VA 3000W / 30A

How the Math Shifts: 120V vs 230V vs 3-Phase Systems

A 1500W load does not draw the same current everywhere. The physical wire size and the internal relays of your d to a converter must be matched to the regional grid standard or your specific off-grid transformer setup. According to fundamental AC theory principles outlined by All About Circuits, here is how the amperage shifts:

120V Single-Phase (North America)

I = 1500W / (120V × 0.8) = 15.6A
You need an inverter capable of outputting at least 16A continuously on a single hot leg. A standard 2000W 120V inverter is the correct pick.

230V Single-Phase (Europe / UK / AU)

I = 1500W / (230V × 0.8) = 8.15A
Because the voltage is nearly double, the current is cut in half. An 8.15A draw is easily handled by a smaller 1000W or 1200W 230V inverter, though a 1500W unit is still recommended for surge headroom.

208V 3-Phase (Industrial / Large Marine)

I = 1500W / (√3 × 208V × 0.8) = 5.2A per leg
Three-phase power distributes the load across three conductors. The current per leg drops to a mere 5.2A. However, 3-phase DC-to-AC converters are highly specialized, expensive, and typically start at 5kW+ capacities. You would use a 5kW 3-phase inverter and simply underutilize its capacity.

Decision Tree: Picking Your Exact D to A Converter

Use this decision-tree-table to terminate your sizing process and select a specific, reliable unit. This path assumes a 12V DC battery bank, which is the most common architecture for mobile and small off-grid setups.

If Your Load Profile Is... And Your Battery Bank Is... Then Choose This Exact Inverter Model
Resistive only (Heaters, lights)
PF = 1.0, Low Surge
12V LiFePO4
(High discharge rate)
AIMS PWRIG200012 (2000W Pure Sine, 120V)
Mixed Inductive (Power tools, fridge)
PF = 0.7, High Surge
12V AGM / Lead-Acid
(Voltage sag under load)
Victron Phoenix 12/2000 (2000W, High surge capability)
Heavy Continuous (AC units, well pumps)
>1800W running
24V or 48V LiFePO4
(Required to keep DC amps safe)
Victron MultiPlus 48/3000 (3000W, Integrated charger)

The Concrete Pick: For the vast majority of 1500W mixed-load scenarios on a 12V system, the Victron Phoenix 12/2000 is the benchmark. It delivers 2000W continuous, handles a 3800W peak surge for motor startups, and features programmable DIP switches to adjust low-voltage shutdown thresholds, protecting your battery bank from deep discharge.

The Hidden Bottleneck: DC-Side Wiring and Voltage Sag

Sizing the AC output is only half the battle. The DC input side of a d to a converter is where most DIY fires start. Inverters are not 100% efficient; a good unit operates at roughly 90% efficiency.

To output 1500W AC, the inverter must pull 1500W / 0.90 = 1666W from the battery. At a nominal 12V, that is 138 Amps. However, under heavy load, a 12V battery bank will sag to roughly 11.5V. At 11.5V, the current spikes to 1666W / 11.5V = 144 Amps.

Per NEC-style guidance for solar and inverter installations (referencing Victron Energy's wiring manuals and standard ampacity derating), you must size your DC cables for 125% of the maximum continuous current. 144A × 1.25 = 180A. Therefore, you must use 2 AWG or 1/0 AWG copper THHN wire for the battery-to-inverter run, paired with a 200A Class T fuse mounted within 18 inches of the battery positive terminal. Never use automotive-style ANL fuses for this primary protection; they lack the high interrupt capacity (AIC) required to safely stop a dead-short on a lithium battery bank.

Frequently Asked Questions

Can I use a modified sine wave d to a converter for inductive loads?
No. Modified sine wave inverters output a stepped square wave that causes inductive motors to run hot, lose 20-30% of their efficiency, and emit a harsh buzzing sound. Always use a pure sine wave inverter for anything with a compressor, fan, or transformer.

What happens if my inverter is rated for 2000W but my battery BMS limits output to 100A?
Your BMS will trip and shut down the system the moment you exceed ~1150W of AC load (1150W / 0.9 efficiency = 1277W DC / 11.5V = 111A). You must either upgrade to a BMS with a higher continuous discharge rating (e.g., 200A) or wire two 100A battery packs in parallel.