When you plug a load into a long cable run, the wire itself acts as a resistor. The voltage that leaves your breaker panel is not the exact voltage that arrives at your outlet or appliance. A voltage drop calculator for cables quantifies this loss, ensuring your equipment receives adequate voltage and your wires don't overheat. While web calculators are convenient, relying on them without understanding the underlying math leads to undersized feeders and tripped breakers. Here is the exact derivation, the common traps, and the worked math you need to size wire with confidence.
The Core Voltage Drop Formula and Symbol Definitions
The fundamental formula used in North America for single-phase AC and DC voltage drop—derived from Ohm's Law and standardized in NEC Chapter 9 informational notes—is based on the wire's cross-sectional area in Circular Mils (CM). The formula is:
Vd = (2 × K × I × L) / CM
| Symbol | Definition | Standard Unit / Value |
|---|---|---|
| Vd | Voltage Drop (the actual volts lost in the wire) | Volts (V) |
| 2 | Multiplier for the complete circuit loop (out and return) | Dimensionless (Use 1.732 for 3-phase) |
| K | Direct Current Constant (Resistivity of the conductor material) | 12.9 for Copper, 21.2 for Aluminum (at 75°C) |
| I | Current (The actual continuous load current, not breaker size) | Amperes (A) |
| L | Length (One-way distance from source to load) | Feet (ft) |
| CM | Circular Mils (Cross-sectional area of the wire) | Circular Mils (e.g., 10 AWG = 10,380 CM) |
Assumptions, Unit Traps, and Realistic Magnitudes
When This Formula Applies (and Its Assumptions)
This formula assumes a single-phase AC circuit with a power factor near 1.0, or a pure DC circuit. For wires smaller than 1/0 AWG, AC reactance is negligible, making this DC-derived approximation highly accurate (within 1-2% of actual measured drop). It also assumes a steady-state load at an ambient temperature of 30°C and a conductor operating temperature of 75°C. If your wire is running through a hot attic (e.g., 110°F+), the K constant increases slightly due to thermal resistance, meaning your actual drop will be marginally higher than calculated.
The Unit Mistakes That Break the Math
When using a voltage drop calculator for cables or doing the math by hand, 90% of errors come from three unit traps:
- The AWG vs. CM Trap: You cannot plug "10" into the CM variable just because you are using 10 AWG wire. You must look up the Circular Mils for 10 AWG in NEC Chapter 9, Table 8 (which is 10,380). Plugging in the AWG number will result in a mathematically absurd voltage drop.
- The Distance Trap: L is the one-way distance. If your total wire spool used is 200 feet for an out-and-back run, L is 100 feet. The "2" in the numerator already accounts for the return path.
- The Load vs. Breaker Trap: I is the actual connected load, not the breaker rating. If you have a 20A breaker but the appliance only draws 12A, use 12A for the voltage drop calculation.
What a Realistic Answer Magnitude Looks Like
The NEC recommends a maximum of 3% voltage drop for branch circuits and 5% total for feeder plus branch. On a standard 120V residential circuit, 3% is exactly 3.6 Volts. If your calculation yields a 45V drop on a 120V branch circuit, you have made a decimal error. Realistic branch circuit drops should generally fall between 0.5V and 4.0V.
Rearranged Forms: Solving for Wire Size, Distance, and Current
A true understanding of the formula means knowing how to algebraically isolate any variable. Here are the rearranged forms you will use on the jobsite:
- Solve for Wire Size (CM): Used when you know the distance and load, and need to find the minimum wire gauge to stay under a 3% drop.
CM = (2 × K × I × L) / Vd - Solve for Max Distance (L): Used when you have a specific wire spool and need to know how far you can run it before exceeding 3% drop.
L = (Vd × CM) / (2 × K × I) - Solve for Max Current (I): Used to find the maximum load an existing wire run can handle without excessive voltage sag.
I = (Vd × CM) / (2 × K × L)
Worked Example 1: Calculating Drop on an Existing 10 AWG Circuit
Scenario: You are extending a 120V circuit to a detached workshop. You are using 10 AWG copper THHN wire in PVC conduit. The one-way distance is 80 feet. The continuous load is a dust collector drawing 15 Amps. What is the voltage drop, and does it meet the 3% NEC guideline?
Step 1: Identify the variables.
- K = 12.9 (Copper)
- I = 15 A
- L = 80 ft
- CM = 10,380 (from NEC Table 8 for 10 AWG solid/stranded copper)
Step 2: Plug into the core formula.
Vd = (2 × 12.9 × 15 × 80) / 10,380
Step 3: Calculate numerator and denominator.
- Numerator: 2 × 12.9 = 25.8. Then 25.8 × 15 = 387. Then 387 × 80 = 30,960
- Denominator: 10,380
Step 4: Divide and find percentage.
Vd = 30,960 / 10,380 = 2.98 Volts
Percentage Drop = (2.98 / 120) × 100 = 2.48%
Verdict: 2.48% is under the 3% maximum. The 10 AWG wire is acceptable for this run regarding voltage drop (assuming it also meets ampacity requirements, which 10 AWG at 30A+ easily does for a 15A load).
Worked Example 2: Sizing Wire for a 240V EV Charger Run
Scenario: You are installing a Level 2 EV charger in a garage. The panel is 120 feet away (one-way). The charger draws a continuous 32 Amps at 240V. You want to limit voltage drop to exactly 3%. What size copper wire do you need?
Step 1: Identify the variables and target.
- K = 12.9 (Copper)
- I = 32 A (Actual continuous load)
- L = 120 ft
- Target Vd = 3% of 240V = 7.2 Volts
Step 2: Use the rearranged formula to solve for CM.
CM = (2 × K × I × L) / Vd
CM = (2 × 12.9 × 32 × 120) / 7.2
Step 3: Calculate numerator and divide.
- Numerator: 2 × 12.9 = 25.8. Then 25.8 × 32 = 825.6. Then 825.6 × 120 = 99,072
- CM = 99,072 / 7.2 = 13,760 CM
Step 4: Select the wire gauge.
Looking at standard wire tables (like those referenced by the Engineering Toolbox copper wire data):
- 10 AWG = 10,380 CM (Too small)
- 8 AWG = 16,510 CM (Larger than 13,760)
Verdict: You must use a minimum of 8 AWG copper wire to maintain a 3% or lower voltage drop on this specific 120-foot run.
Wire Sizing Decision Tree: From Calculation to Concrete AWG Pick
Math gives you a Circular Mil requirement, but the hardware store sells AWG. Use this decision path to translate your calculator output into a physical wire purchase. Note that ampacity (fire safety) always trumps voltage drop (performance). You must satisfy both.
| If Your Calculated CM Is... | And Minimum Ampacity Requires... | Then Your Final Concrete Pick Is... |
|---|---|---|
| ≤ 6,530 CM | 12 AWG (20A circuit) | 12 AWG Copper |
| 6,531 to 10,380 CM | 10 AWG (30A circuit) | 10 AWG Copper |
| 10,381 to 16,510 CM | 8 AWG (40A circuit) | 8 AWG Copper |
| 16,511 to 26,240 CM | 6 AWG (50A/60A circuit) | 6 AWG Copper |
| > 26,240 CM | 4 AWG or larger | 4 AWG Copper (or 2 AWG Aluminum) |
By mastering the Vd = (2 × K × I × L) / CM formula and tracking your units rigorously, you transition from blindly trusting web apps to engineering your wire runs with precision. Always verify your final AWG selection against the National Electrical Code ampacity tables to ensure the wire can safely handle the breaker's fault current without melting the insulation.






