The terminal voltage of an electrochemical cell under load is calculated using the formula Vt = E - (I × ri), where Vt is terminal voltage, E is open-circuit electromotive force (EMF), I is current, and ri is internal resistance. For example, if a Samsung 30Q 18650 Li-ion cell has an EMF of 3.60V and an internal resistance of 0.020Ω while drawing 10A, the terminal voltage is 3.40V.

Deriving the Core Formula for Cell Voltage

An ideal electrochemical cell would maintain a constant voltage regardless of the current drawn. However, real-world cells contain electrolytes, separators, and electrodes that physically oppose current flow. In circuit theory, we model this reality using an ideal voltage source (E) in series with an internal resistor (ri).

To derive the formula, we apply Kirchhoff's Voltage Law (KVL) around the discharge loop. The sum of the voltage rises and drops must equal zero:

E - Vdrop - Vt = 0

Substituting Ohm's Law (Vdrop = I × ri) into the KVL equation gives us:

E - (I × ri) - Vt = 0

Solving for terminal voltage yields the core working formula:

Vt = E - (I × ri)

Every variable in this equation must be tracked precisely. According to Georgia State University HyperPhysics, confusing the ideal EMF with the measurable terminal voltage is the most common error in introductory circuit analysis.

Table 1: Formula Symbol Definitions and Units
SymbolVariable NameStandard UnitPhysical Meaning
VtTerminal VoltageVolts (V)The actual voltage measured across the cell's terminals while current is flowing.
EElectromotive Force (EMF)Volts (V)The open-circuit voltage (OCV) measured when zero current is flowing. Dictated by cell chemistry and State of Charge (SoC).
ILoad CurrentAmperes (A)The rate of electron flow drawn from the cell by the external circuit.
riInternal ResistanceOhms (Ω)The inherent opposition to current flow inside the cell, causing energy loss as heat.

Rearranged Forms: Solving for Every Variable

On the workbench, you rarely have all four variables. You might need to find the internal resistance of an aging battery pack or calculate the maximum safe current draw. Here are the algebraic rearrangements of the core formula:

  • Solve for EMF (E): E = Vt + (I × ri)
    Use case: Finding the true open-circuit voltage when you can only measure the cell under a known load.
  • Solve for Current (I): I = (E - Vt) / ri
    Use case: Determining the exact current draw if you know the cell's OCV, its internal resistance, and the minimum acceptable cutoff voltage.
  • Solve for Internal Resistance (ri): ri = (E - Vt) / I
    Use case: The standard DC load-test method for calculating the health and aging of a cell by measuring voltage sag under a known current.

Worked Examples with Unit Tracking

Abstract formulas fail when unit conversions are ignored. Below are two real-world scenarios with strict unit tracking.

Problem 1: Calculating Terminal Voltage for a High-Drain Li-ion Cell

Scenario: You are building a 3S1P drone battery using Samsung 30Q 18650 cells. One cell has an open-circuit voltage (E) of 4.10V. The datasheet lists a DC internal resistance (ri) of 15mΩ. The drone's motor controller draws 20A (I) from the cell during a punch-out. What is the terminal voltage (Vt)?

  1. Convert units to base SI: Internal resistance is given in milliohms. 15mΩ = 0.015Ω.
  2. Apply the formula: Vt = E - (I × ri)
  3. Substitute values: Vt = 4.10V - (20A × 0.015Ω)
  4. Calculate the voltage drop: 20 × 0.015 = 0.30V
  5. Final subtraction: Vt = 4.10V - 0.30V = 3.80V

Result: The cell's terminal voltage sags to 3.80V under load. This is well above the typical 2.5V low-voltage cutoff, meaning the cell is operating safely.

Problem 2: Calculating Internal Resistance of an Aging Lead-Acid Battery

Scenario: A 12V flooded lead-acid battery in a solar backup system shows an open-circuit voltage (E) of 12.60V. When a 150A (I) inverter surge hits, a multimeter on the terminals reads a loaded voltage (Vt) of 11.40V. What is the internal resistance (ri)?

  1. Select the rearranged formula: ri = (E - Vt) / I
  2. Substitute values: ri = (12.60V - 11.40V) / 150A
  3. Calculate the numerator (voltage sag): 12.60 - 11.40 = 1.20V
  4. Divide by current: ri = 1.20V / 150A = 0.008Ω
  5. Convert to milliohms for readability: 0.008Ω × 1000 = 8mΩ

Result: An internal resistance of 8mΩ for a standard 12V lead-acid battery indicates moderate sulfation or aging. A healthy Optima RedTop of similar size would typically measure closer to 3mΩ.

Assumptions, Unit Traps, and Realistic Magnitudes

The formula Vt = E - (I × ri) is a linear DC approximation. To use it accurately, you must understand its boundaries.

When the Formula Applies (and Its Assumptions)

  • Steady-State DC: The formula assumes a constant DC load. It does not account for the transient voltage recovery caused by the electrochemical double-layer capacitance immediately after a load is removed.
  • Constant Temperature: Internal resistance is highly temperature-dependent. A cell at 0°C will have a significantly higher ri than the same cell at 25°C. The formula assumes isothermal conditions during the measurement.
  • Linear Resistance: It assumes ri is constant across the discharge curve. In reality, ri increases non-linearly as the cell approaches 0% State of Charge (SoC).
⚠ The Milliohm Unit Trap

The most frequent mathematical failure in battery building is forgetting to convert milliohms (mΩ) to ohms (Ω). If you plug 15mΩ into the formula as "15" instead of "0.015", a 10A load calculation yields a voltage drop of 150V, resulting in a physically impossible negative terminal voltage. Always divide mΩ by 1,000 before calculating. For deeper diagnostics on measuring these tiny resistances, refer to the load-testing protocols outlined by Battery University.

Realistic Answer Magnitudes Reference Chart

Knowing what a "normal" answer looks like prevents you from trusting a flawed multimeter reading or a bad calculation. Below are baseline values for common cell chemistries at 50% SoC and 25°C.

Table 2: Realistic EMF and Internal Resistance Magnitudes by Cell Chemistry
Cell Type & Model ExampleNominal EMF (E)Typical ri (New)Expected Vt Sag at 10A
Alkaline AA (Duracell Coppertop)1.50V0.150Ω (150mΩ)1.50V drop (Cannot sustain 10A)
Li-ion 18650 Standard (Panasonic NCR18650B)3.60V0.050Ω (50mΩ)0.50V drop
Li-ion 18650 High-Drain (Samsung 30Q)3.60V0.020Ω (20mΩ)0.20V drop
LiFePO4 Prismatic (EVE 100Ah)3.20V0.0005Ω (0.5mΩ)0.005V drop
Lead-Acid 12V AGM (Optima D34)12.60V0.003Ω (3mΩ)0.03V drop

Frequently Asked Questions

How to calculate voltage of a cell without a multimeter?

If you cannot measure the loaded voltage directly but you know the exact resistance of your external load (Rload), you can calculate the terminal voltage using the voltage divider principle derived from the core formula. The equation is: Vt = E × [Rload / (Rload + ri)]. For example, if a 3.7V cell with 0.05Ω internal resistance is connected to a 1.0Ω heating element, the terminal voltage is 3.7 × [1.0 / (1.0 + 0.05)] = 3.52V. This assumes the load is purely resistive and does not change resistance as it heats up.

How do I calculate the voltage of a cell in a series battery pack?

When cells are wired in series, both the electromotive force and the internal resistance scale linearly with the number of cells (N). The modified formula for a series pack is: Vpack = (N × E) - (I × N × ri). For a 4S Li-ion pack (N=4) where each cell has an E of 3.8V and an ri of 0.020Ω, drawing 15A yields: Vpack = (4 × 3.8) - (15 × 4 × 0.020) = 15.2V - 1.2V = 14.0V. Note that this assumes all cells in the series string are perfectly matched in capacity and internal resistance; a single weak cell will skew the real-world measurement.

Why does my calculated cell voltage differ from the datasheet nominal voltage?

Datasheet "nominal" voltage (e.g., 3.6V for Li-ion, 1.2V for NiMH, 2.0V for Lead-Acid) is an engineering average representing the relatively flat middle section of the discharge curve. It is not a physical constant. Your calculated Vt will almost always differ from nominal because the actual EMF (E) fluctuates based on the exact State of Charge (SoC). A fully charged Li-ion cell has an E of 4.20V, while a depleted one rests at 3.00V. Always use the measured open-circuit voltage (E) for your calculations, never the printed nominal voltage, to ensure mathematical accuracy.